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0=-4.9x^2+5x+2
We move all terms to the left:
0-(-4.9x^2+5x+2)=0
We add all the numbers together, and all the variables
-(-4.9x^2+5x+2)=0
We get rid of parentheses
4.9x^2-5x-2=0
a = 4.9; b = -5; c = -2;
Δ = b2-4ac
Δ = -52-4·4.9·(-2)
Δ = 64.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{64.2}}{2*4.9}=\frac{5-\sqrt{64.2}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{64.2}}{2*4.9}=\frac{5+\sqrt{64.2}}{9.8} $
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